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Table 5 Parameters estimation and likelihood ratio tests for the branch-site models

From: Unusual tandem expansion and positive selection in subgroups of the plant GRAS transcription factor superfamily

Foreground branches

Estimates of parameter

positive selection sites (BEB) 4

Site class 10

Site class 1

Site class 2a

Site class 2b

Group I

P0 = 0.50799

P1 = 0.05716

P2a = 0.39087

P2b = 0.04398

296Q*,337A*,397 K*,407D*,

ω0(b)2 = 0.13998

ω1(b) = 1.00000

ω2a(b) = 0.13998

ω2b(b) = 1.00000

412 L*,415P**,419H*,446 T*,

ω0(f)3 = 0.13998

ω1(f) = 1.00000

ω2a(f) = 3.03087

ω2b(f) = 3.03087

453 F**,457 L*,464C*,476E**, 505 T**,510Q*,527A*, 535 V*

Group II

P0 = 0.63235

P1 = 0.07147

P2a = 0.26611

P2b = 0.03007

644 L*

ω0(b) = 0.13987

ω1(b) = 1.00000

ω2a(b) = 0.13987

ω2b(b) = 1.00000

ω0(f) = 0.13987

ω1(f) = 1.00000

ω2a(f) = 1.16777

ω2b(f) = 1.16777

Group III

P0 = 0.69273

P1 = 0.07803

P2a = 0.20604

P2b = 0.02321

None

ω0(b) = 0.14005

ω1(b) = 1.00000

ω2a(b) = 0.14005

ω2b(b) = 1.00000

ω0(f) = 0.14005

ω1(f) = 1.00000

ω2a(f) = 999.00000

ω2b(f) = 999.00000

Group IV

P0 = 0.86848

P1 = 0.04356

P2a = 0.08376

P2b = 0.00420

328Q*, 368S**

ω0(b) = 0.13026

ω1(b) = 1.00000

ω2a(b) = 0.13026

ω2b(b) = 1.00000

ω0(f) = 0.13026

ω1(f) = 1.00000

ω2a(f) = 20.88429

ω2b(f) = 20.88429

Group V

P0 = 0.63670

P1 = 0.03187

P2a = 0.31563

P2b = 0.01580

296Q**,303A**,412 L**,418 F*, 453 F*,490 W**,497D**,508 L**, 511R**, 513A**, 518 T**,

ω0(b) = 0.12995

ω1(b) = 1.00000

ω2a(b) = 0.12995

ω2b(b) = 1.00000

ω0(f) = 0.12995

ω1(f) = 1.00000

ω2a(f) = 1.56269

ω2b(f) = 1.56269

Group VI

P0 = 0.72413

P1 = 0.03621

P2a = 0.22825

P2b = 0.01141

448 K*, 456 K**, 515 K**

ω0(b) = 0.12948

ω1(b) = 1.00000

ω2a(b) = 0.12948

ω2b(b) = 1.00000

ω0(f) = 0.12948

ω1(f) = 1.00000

ω2a(f) = 1.26601

ω2b(f) = 1.26601

Group VII

P0 = 0.71371

P1 = 0.03569

P2a = 0.23866

P2b = 0.01194

297C**, 335S*, 497D*, 551R*

ω0(b) = 0.12951

ω1(b) = 1.00000

ω2a(b) = 0.12951

ω2b(b) = 1.00000

ω0(f) = 0.12951

ω1(f) = 1.00000

ω2a(f) = 76.78801

ω2b(f) = 76.78801

  1. Note: *p < 0.05 and **p < 0.01 (x 2 test).
  2. 1The sites in the sequence evolve according to the same process, the transition probability matrix is calculated only once for all sites for each branch.
  3. 2Background ω.
  4. 3Foreground ω.
  5. 4The number of amino acid sites estimated to have undergone positive selection; BEB: Bayes Empirical Bayes.